(27x^4-18x^3+9x^2)/3x

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Solution for (27x^4-18x^3+9x^2)/3x equation: 


x in (-oo:+oo)

x*((27*x^4-(18*x^3)+9*x^2)/3) = 0

x*((27*x^4-18*x^3+9*x^2)/3) = 0

(x*(27*x^4-18*x^3+9*x^2))/3 = 0

27*x^4-18*x^3+9*x^2 = 0

9*x^2*(3*x^2-2*x+1) = 0

3*x^2-2*x+1 = 0

DELTA = (-2)^2-(1*3*4)

DELTA = -8

DELTA < 0

9*x^2 = 0

(9*x*x^2)/3 = 0

( 9*x^2 )

9*x^2 = 0 // : 9

x^2 = 0

x = 0

( x )

x = 0

x in { 0, 0 }

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